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15x^2-100x=-125
We move all terms to the left:
15x^2-100x-(-125)=0
We add all the numbers together, and all the variables
15x^2-100x+125=0
a = 15; b = -100; c = +125;
Δ = b2-4ac
Δ = -1002-4·15·125
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-50}{2*15}=\frac{50}{30} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+50}{2*15}=\frac{150}{30} =5 $
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